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The real value of $' a '$ for which $\;3i^{3}-2ai^{2}+(1-a)i+5\;$ is real is


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Answer : $-\;2$
Explanation :
$\;3i^{3}-2ai^{2}+(1-a)i+5\; =-3i+2a+5+(1-a)i $
$=2a+5+i(-a-2)\;$, which is real
If $\;-a-2 =0\; i .e \;a=-2$
answered Apr 17, 2014 by yamini.v

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