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If $\;|z|=2\;$ and $\;arg(z) = \large\frac{\pi}{4}\;$ , then $\;z=$

$(a)\;\sqrt{3}(1+i)\qquad(b)\;\sqrt{2}(1+i)\qquad(c)\;1+i\qquad(d)\;\sqrt{5}(2+i)$

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1 Answer

Answer : $\;\sqrt{2}(1+i)$
Explanation :
$z=|z| (cos \large\frac{\pi}{4} + i sin\large\frac{\pi}{4})$
$= 2 (\large\frac{1}{\sqrt{2}} +i \large\frac{1}{\sqrt{2}} )$
$=\sqrt{2}(1+i)\;.$
answered Apr 17, 2014 by yamini.v
 

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