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$1+i+i^{2}+i^{3} + i^{4}+i^{5}+i^{6}---+i^{2n}\;$ is


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Answer : Can not be evaluated
Explanation :
$1+i+i^{2}+i^{3} + i^{4}+i^{5}+i^{6}---+i^{2n}\; =1-1+1-1--+(-1)^{n} $
Which Can not be evaluated unless n is known .
answered Apr 18, 2014 by yamini.v
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