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If the complex number $\;z=x+iy\;$ satisfies the condition $\;|z+1|=1\;$ , then z lies on

(a) x - axis\[\](b) Circle with centre (1,0) and radius 1\[\](c) Circle with centre (-1,0) and radius 1\[\](d) y - axis

1 Answer

Answer : Circle with centre (-1,0) and radius 1
Explanation :
$|z+1| =1$
$|(x+1)+iy| =1$
$(x+1)^{2} + y^{2} =1^{2}$
Which is a Circle with centre (-1,0) and radius 1 .
answered Apr 18, 2014 by yamini.v
 

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