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# If $\tan\theta=3$ and $\theta$ lies in third quadrant then the value of $\sin \theta$ is

$\begin{array}{1 1}(A)\;\large\frac{1}{\sqrt {10}}&(B)\;\large\frac{-1}{\sqrt {10}}\\(C)\;\large\frac{-3}{\sqrt {10}}&(D)\;\large\frac{3}{\sqrt {10}}\end{array}$

$\sin \theta=\large\frac{-3}{\sqrt {10}}$
Hence (C) is the correct answer.