# If $e$ and $e'$ be the eccentricities of a hyperbola and its conjugate then $\large\frac {1}{e^2}+\frac{1}{e^{12}}$ is equal to
$\begin{array}{1 1}(A)\;0 \\(B)\;1 \\(C)\;2 \\(D)\;none\;of\;these \end{array}$