info@clay6.com
+91-9566306857
Ask Questions, Get Answers
Menu
X
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
15 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
CBSE XII Board Exam Series
BES Math
BES Physics
BES Chemistry
BES Biology
studyplans
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
15 Test Series
CBSE XII
Math
JEEMAIN
Math
Physics
Chemistry
Practice Test Series
CBSE XI
Math
NEET
Physics
Chemistry
Biology - XII
Biology - XI
Olympiad class V
Math - 5 Test Series
Olympiad class VI
Math - 5 Test Series
CBSE XII Board Exam Series
BES Math
BES Physics
BES Chemistry
BES Biology
mobile
exams
ask
sample papers
tutors
pricing
login
X
ASK
Home
>>
JEEMAIN and NEET
>>
Mathematics
>>
Class11
>>
Coordinate Geometry
Find the equation of hyperbola if the distance between the foic is $16, e=\sqrt 2$ and axis along x-axis with centre oxgin.
$\begin{array}{1 1}(A)\;x^2+y^2=8 \\(B)\;x^2-y^2=32 \\(C)\;x^2+y^2=1 \\(D)\;x^2+y^2=64 \end{array}$
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
medium
Share
asked
Apr 21, 2014
by
meena.p
retagged
Sep 27, 2014
by
sharmaaparna1
Please
log in
or
register
to add a comment.
Please
log in
or
register
to answer this question.
1 Answer
$b^2=a^2(e^2-1)$
=> $b^2=a^2$
=> $b=a$
$2ae=16$
$a=4 \sqrt 2$
Since $e=\sqrt 2$ given
Equation of hyperbola is
$\large\frac{x^2}{32}-\frac{y^2}{32}$$=1$
or $x^2-y^2=32$
Hence B is the correct answer.
answered
Apr 21, 2014
by
meena.p
Please
log in
or
register
to add a comment.
Related questions
The distance between the foci of a hyperbola is $16$ and its eccentricity is $\sqrt 2$. Its equation is
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
medium
asked
Apr 21, 2014
by
meena.p
1
answer
Find the equation of the hyperbola with focus $(2,2) \; e=2$ and directrise $x+y=9$
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
medium
asked
Apr 10, 2014
by
meena.p
1
answer
The eccentricity of the hyperbola whose latus rectum is $8$ and conjugate axis is equal to half the distance between the foci is
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
difficult
asked
Apr 11, 2014
by
meena.p
1
answer
Find the equation of an rectangular hyperbola whose centre is origin and its asymptotes coincide with the co-ordinate axes?
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
q121
medium
asked
Feb 10, 2014
by
sreemathi.v
1
answer
If vertex and focus of hyperbola are $(2,3)$ and $(6,3)$ respectively and eccentricity e of the hyperbola is 2 then equation of the hyperbola is
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
medium
asked
Apr 21, 2014
by
meena.p
1
answer
The foci of a hyperbola coincide with the foci of the ellipse $\large\frac{x^2}{25}+\frac{y^2}{9}$$=1$.Find the equation of the hyperbola if its ecentricity is 3?
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
q110
medium
asked
Feb 10, 2014
by
sreemathi.v
1
answer
A rectangular hyperbola whose cetre is C is cut by any circle of radius r in four points $P,Q,R$ and S. Then $CP^2+CQ^2+CR2+CS^2$ is equal to.
jeemain
math
class11
coordinate-geometry-conic -sections
hyperbola
ch11
medium
asked
Apr 21, 2014
by
meena.p
1
answer
Ask Question
Tag:
Math
Phy
Chem
Bio
Other
SUBMIT QUESTION
►
Please Wait
Take Test
JEEMAIN Crash Practice
15 Test Series
NEET Crash Practice
15 Test Series
JEEMAIN
350+ TESTS
NEET
320+ TESTS
CBSE XI MATH
50+ TESTS
CBSE XII MATH
80+ TESTS
...
close