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Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
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Find the equation of hyperbola if the distance between the foic is $16, e=\sqrt 2$ and axis along x-axis with centre oxgin.

$\begin{array}{1 1}(A)\;x^2+y^2=8 \\(B)\;x^2-y^2=32 \\(C)\;x^2+y^2=1 \\(D)\;x^2+y^2=64 \end{array}$

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=> $b^2=a^2$
=> $b=a$
$a=4 \sqrt 2$
Since $e=\sqrt 2$ given
Equation of hyperbola is
or $x^2-y^2=32$
Hence B is the correct answer.
answered Apr 21, 2014 by meena.p

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