Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Mathematics  >>  Class11  >>  Coordinate Geometry
0 votes

The eccentricity of the hyperbola $9y^2 -4x^2=36$ is

$\begin{array}{1 1}(A)\;\frac{5}{2} \\(B)\;\frac{\sqrt 7}{2} \\(C)\;\sqrt \frac{13}{2} \\(D)\;2 \end{array}$

Can you answer this question?

1 Answer

0 votes
here the coefficient $y^2$ is +ve and that of $x^2$ is $-ve$
and hence it represents a hyperbola whose transverse axis is vertical
i.e $a^2=4$
$e= \large\frac{\sqrt {13}}{2}$
Hence C is the correct answer.
answered Apr 21, 2014 by meena.p

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App