$e=\large\frac{3}{2}$
$2ae=4$
$\therefore a=\large\frac{4}{3}$
$b^2=a^2(e^2-1)$
$\large\frac{16}{9} . \frac{5}{4}=\frac{20}{9}$
$9 \bigg(\frac{x^2}{16} -\frac{y^2}{20} \bigg)=1$
$\large\frac{x^2}{4}-\frac{y^2}{5}=\frac{4}{9} $
Hence A is the correct answer.