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# Equation of the hyperbola with eccentricity $\large\frac{3}{2}$ and foci at $(\pm2,0)$ is

$\begin{array}{1 1}(A)\;\frac{x^2}{4}-\frac{y^2}{5}=\frac{4}{9} \\(B)\;\frac{x^2}{9}-\frac{y^2}{9}=\frac{4}{9} \\(C)\;\frac{x^2}{4}-\frac{y^2}{9}=1 \\(D)\;none\;of\;these \end{array}$