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Home  >>  CBSE XI  >>  Math  >>  Trigonometric Functions
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The value of $\large\frac{\sin 50^{\large\circ}}{\sin 130^{\large\circ}}$ is ________

$\begin{array}{1 1}(A)\;\sqrt 2&(B)\;1\\(C)\;\sqrt 3&(D)\;\large\frac{1}{2}\end{array} $

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  • $\sin (\pi-\theta)=\sin \theta$
$\large\frac{\sin 50^{\large\circ}}{\sin (180-50)^{\large\circ}}=\frac{\sin 50^{\large\circ}}{\sin 50^{\large\circ}}$
$\Rightarrow 1$
Hence (B) is the correct answer.
answered Apr 22, 2014 by sreemathi.v
 

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