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Home  >>  CBSE XI  >>  Math  >>  Trigonometric Functions
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Find the value of $cosec(-\large\frac{41\pi}{4})$

$\begin{array}{1 1}(A)\;-\sqrt 2&(B)\;-\sqrt 3\\(C)\;2&(D)\;-2\end{array} $

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1 Answer

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  • $cosec(\theta+2n\pi)=cosec \theta$
$cosec(-\large\frac{41\pi}{4})=$$-cosec(-\large\frac{41\pi}{4})$
$\sin (-\theta)=\sin \theta$
$-cosec(\large\frac{41\pi}{4})=$$-cosec(10\pi+\large\frac{\pi}{4})$
$-cosec \large\frac{\pi}{4}$$=-\sqrt 2$
Hence (A) is the correct answer.
answered Apr 22, 2014 by sreemathi.v
 
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