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If the system of linear equations :$x+2ay+az=0,x+3by+bz=0,x+4cy+cz=0$ has a zero solutions then $a,b,c$

$\begin{array}{1 1}(A)\;\text{are in G.P}&(B)\;\text{are in H.P}\\(C)\;\text{satisfy a+2b+3c=0}&(D)\;\text{are in A.P}\end{array}$

1 Answer

For non-zero solution,we have
On expanding along $R_1$ we get
$\Rightarrow 2ac=ab+bc$
$\Rightarrow a,b,c$ in H.P
Hence (B) is the correct answer.
answered Apr 24, 2014 by sreemathi.v

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