Browse Questions

# The number of right inverse for the matrix $\begin{bmatrix}1&-1&2\\2&-1&1\end{bmatrix}$

$\begin{array}{1 1}(A)\;0&(B)\;1\\(C)\;2&(D)\;\text{Infinite}\end{array}$

Let right inverse is $\begin{bmatrix}a&b\\c&d\\e&f\end{bmatrix}$
Now $a-c+2e=1$
$b-d+2f=0$
$2a-c+e=0$
$2b-d+f=1$ infinite solution.
Hence (d) is the correct answer.