logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

In the circuit shown here , the point ' C ' is kept connected to point ' A ' till the current flowing through the circuit becomes constant . Afterward ,suddenly , point ' C ' is disconnected from point ' A ' and connected to point ' B ' at time t=0 . Ratio of the voltage across resistance and the inductor at $\;t=\large\frac{L}{R}\;$ will be equal to :

$(a)\;\large\frac{e}{1-e}\qquad(b)\;1\qquad(c)\;-1\qquad(d)\;\large\frac{1-e}{e}$

Can you answer this question?
 
 

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...