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The correct set of four quantum numbers for the valence electrons of rubidium atom (z=37) is :

$(a)\;5,0,0,+\large\frac{1}{2}\qquad(b)\;5,1,0,+\large\frac{1}{2}\qquad(c)\;5,1,1,+\large\frac{1}{2}\qquad(d)\;5,0,1,+\large\frac{1}{2}$

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