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Find the slope of the tangent to the curve $x^2+y^2=4x-2$at the point (3,1)

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Diffrentiating the eqn w.r.t x we have 2x + 2y dy\dx = 4 2y dy\dx = 4 - 2x dy\dx = (4 - 2x)\2y (4 - 2×3)\2×1 (4 - 6)\2 -2\2 -1 ans.
answered Apr 3, 2016 by sarveshchauhan185
 

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