Browse Questions

Find the slope of the tangent to the curve $x^2+y^2=4x-2$at the point (3,1)

Diffrentiating the eqn w.r.t x we have 2x + 2y dy\dx = 4 2y dy\dx = 4 - 2x dy\dx = (4 - 2x)\2y (4 - 2×3)\2×1 (4 - 6)\2 -2\2 -1 ans.