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In the reaction , $\;CH_{3}OOH\; \underrightarrow{LiAlH_{4}}\; A \; \underrightarrow{PCl_{5}}\;B\;\underrightarrow{Alc.KOH}\;C \; $ , the product C is :

$(a)\;Acetaldehyde\qquad(b)\;Acetylene\qquad(c)\;Ethylene\qquad(d)\;Acetyl\;chloride$

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