# Temperature of $4 mol$ of an ideal gas occupying $5 dm^3$ at $3.32\; bar \; (R= 0.083\;bar \;dm^3 K)$

$(A)\;50 \\ (B) \; 100 \\ (C)\;323 \\ (D)\;373$

Since , $PV= nRT$
$3.32 \times 5 =4 \times 0.083 \times T$
$T=50$
Hence A is the correct answer.