Browse Questions

# The image of the line $\;\large\frac{x-1}{3} =\large\frac{y-3}{1} =\large\frac{z-4}{-5}\;$ in the plane $\;2x-y+z+3=0\;$ is the plane :

$(a)\;\large\frac{x-3}{3} =\large\frac{y+5}{1} =\large\frac{z-2}{-5} \qquad(b)\;\large\frac{x-3}{-3} =\large\frac{y+5}{-1} =\large\frac{z-2}{5}\qquad(c)\;\large\frac{x+3}{3} =\large\frac{y-5}{1} =\large\frac{z-2}{-5}\qquad(d)\;\large\frac{x+3}{-3} =\large\frac{y-5}{-1} =\large\frac{z+2}{5}$