logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

The image of the line $\;\large\frac{x-1}{3} =\large\frac{y-3}{1} =\large\frac{z-4}{-5}\;$ in the plane $\;2x-y+z+3=0\;$ is the plane :

$(a)\;\large\frac{x-3}{3} =\large\frac{y+5}{1} =\large\frac{z-2}{-5} \qquad(b)\;\large\frac{x-3}{-3} =\large\frac{y+5}{-1} =\large\frac{z-2}{5}\qquad(c)\;\large\frac{x+3}{3} =\large\frac{y-5}{1} =\large\frac{z-2}{-5}\qquad(d)\;\large\frac{x+3}{-3} =\large\frac{y-5}{-1} =\large\frac{z+2}{5}$

Can you answer this question?
 
 

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...