logo

Ask Questions, Get Answers

 
X
 Search
Want to ask us a question? Click here
Browse Questions
Ad
0 votes

An experiment is performed to obtain the value of acceleration due to gravity g by using a simple pendulum of length L .In this experiment time for 100 oscillations is measured by using a watch of 1 second least count and the value is 90.0 seconds .The length L is measured by using a meter scale of least count 1 mm and the value is 20.0 cm.The error in the determination of g would be :

$(a)\;1.7 \%\qquad(b)\;2.7 \%\qquad(c)\;4.4 \%\qquad(d)\;2.27 \%$

Can you answer this question?
 
 

Please log in or register to answer this question.

Ask Question
student study plans
x
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App
...