The position of a projectile launched from the origin at t=0 is given by $\;\overrightarrow{r}=(40 \hat{i} + 50 \hat{j}) \;m\;$ at $\;t=2s\;$. If the projectile was launched at an angle $\;\theta\;$ from the horizontal , then $\;\theta\;$ is (take $\;g=10\;ms^{-2}$). - Clay6.com, a Free resource for your JEE, AIPMT and Board Exam preparation

The position of a projectile launched from the origin at t=0 is given by $\;\overrightarrow{r}=(40 \hat{i} + 50 \hat{j}) \;m\;$ at $\;t=2s\;$. If the projectile was launched at an angle $\;\theta\;$ from the horizontal , then $\;\theta\;$ is (take $\;g=10\;ms^{-2}$).