Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

The position of a projectile launched from the origin at t=0 is given by $\;\overrightarrow{r}=(40 \hat{i} + 50 \hat{j}) \;m\;$ at $\;t=2s\;$. If the projectile was launched at an angle $\;\theta\;$ from the horizontal , then $\;\theta\;$ is (take $\;g=10\;ms^{-2}$).

$(a)\;tan^{-1} \large\frac{2}{3} \qquad(b)\;tan^{-1} \large\frac{3}{2} \qquad(c)\;tan^{-1} \large\frac{7}{4} \qquad(d)\;tan^{-1} \large\frac{4}{5} $

Can you answer this question?

Please log in or register to answer this question.

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App