A capillary tube is immersed vertically in water and the height of the water column is x .When this arrangement is taken into a mine of depth d , the height of the water column is y .If R is the radius of the earth , the ratio $\;\large\frac{x}{y}\;$ is :

Question

$(a)\;(1-\large\frac{d}{R}) \qquad(b)\;(1-\large\frac{2d}{R})\qquad(c)\;(\large\frac{R-d}{R+d})\qquad(d)\;(\large\frac{R+d}{R-d})$