$\begin{array}{1 1} \big(-\large\frac{4}{5},\frac{1}{5},\frac{27}{5}\big) \\ (-8,17,3) \\ \big(\large\frac{8}{5},\frac{17}{5},\frac{27}{5}\big) \\\big(-\large\frac{8}{5},\frac{1}{5},\frac{27}{5}\big)\end{array} $

Want to ask us a question? Click here

Browse Questions

Ad |

0 votes

0 votes

- Section formula: The coordinates of the point $C$ that divides the segment joining the points $A(x_1,y_1,z_1)$ and $B(x_2,y_2,z_2)$ in the ratio $l:m$ externally is given by $C\big(\large\frac{lx_2-mx_1}{l-m},\frac{ly_2-my_1}{l-m},\frac{lz_2-mz_1}{l-m}\big)$

Given two points are $A(-2,3,5)$ and $B(1,-4,6)$

We know that from section formula the coordinates of the point $C$ that divides

the segment joining the points $A(x_1,y_1,z_1)$ and $B(x_2,y_2,z_2)$ in the ratio $l:m$ externally is given by

$C\big(\large\frac{lx_2-mx_1}{l-m},\frac{ly_2-my_1}{l-m},\frac{lz_2-mz_1}{l-m}\big)$

$\therefore $ the coordinates of the point $C$ which divides $AB$ in the ratio $2:3$ externally is

$C\big(\large\frac{2.1-3.(-2)}{2-3},\frac{2.(-4)-3.3}{2-3},\frac{2.6-3.5}{2-3}\big)$

$=C(-8,17,3)$

Ask Question

Tag:MathPhyChemBioOther

Take Test

x

JEE MAIN, CBSE, NEET Mobile and Tablet App

The ultimate mobile app to help you crack your examinations

...