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# In the hydroboration - oxidation reaction of propene with diborane , $\;H_{2}O_{2}\;$ and $\;NaOH\;$ the organic compound formed is :

$(a)\;CH_{3}CH_{2}OH\qquad(b)\;CH_{3}CHOHCH_{3}\qquad(c)\;CH_{3}CH_{2}CH_{2}OH\qquad(d)\;(CH_{3})_{3}COH$