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# If an earthworm is left in 90% KOH solution for a long time,which part of it would be left undissolved:-

$\begin{array}{1 1}(A)\;\text{Setae}\\(B)\;\text{Spermatheca}\\(C)\;\text{Sand particles}\\(D)\;\text{Circular muscles}\end{array}$

Chitin is dissolved in KOH
Hence (A) is the correct answer.

A , setae of the earthworm