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If we increases the pressure by 20atm on a sphere which is made up of material of bulkmodulus $5.2\times 10^{10}N/m^2$,what is change in volume percentage?

$\begin{array}{1 1}(A)\;.0001\%\\(B)\;.0038\%\\(C)\;.0023\%\\(D)\;\text{None of these}\end{array} $

1 Answer

$\Delta P$=20atm
$\Rightarrow 20\times 10^5N/m^2$
As $B=\large\frac{\Delta P}{\Delta V/V}$
$\Rightarrow \large\frac{\Delta V}{V}=\frac{\Delta P}{B}$
$\Rightarrow \large\frac{20\times 10^5}{5.2\times 10^{10}}$
$\Rightarrow 3.84\times 10^{-5}$
$\Rightarrow 6\times 10^3\times 9.8\times 760$
$\Rightarrow$ .0038%
Hence (B) is the correct answer.
answered May 7, 2014 by sreemathi.v
 

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