$\begin{array}{1 1}(A)\;.0001\%\\(B)\;.0038\%\\(C)\;.0023\%\\(D)\;\text{None of these}\end{array} $

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$\Delta P$=20atm

$\Rightarrow 20\times 10^5N/m^2$

As $B=\large\frac{\Delta P}{\Delta V/V}$

$\Rightarrow \large\frac{\Delta V}{V}=\frac{\Delta P}{B}$

$\Rightarrow \large\frac{20\times 10^5}{5.2\times 10^{10}}$

$\Rightarrow 3.84\times 10^{-5}$

$\Rightarrow 6\times 10^3\times 9.8\times 760$

$\Rightarrow$ .0038%

Hence (B) is the correct answer.

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