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Home  >>  CBSE XI  >>  Math  >>  Straight Lines
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Reduce the following equation into slope - intercept form and find their slopes and the $y$ - intercepts. $6x+3y-5=0$

$\begin{array}{1 1}(A)\;m = -2 ; c = \large\frac{5}{3} \\(B)\; m = 2; c = -\large\frac{5}{3} \\(C)\; m = \large\frac{1}{2} ; c = \large\frac{5}{3} \\(D)\;m = -\large\frac{1}{2} ; c = -\large\frac{5}{3} \end{array} $

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  • Slope intercept form of an equation is $y=mx+c$ where $m$ is the slope and $c$ is the $y$ intercept
Given equation is $6x+3y-5=0$
This can be written as
$ \qquad 3y=-6x+5$
$ \quad \Rightarrow y = -\large\frac{6}{3}$$x+\large\frac{5}{3}$
or $ y= -2x+5$
This is of the form $y=mx+c$
Here $m = -2$ and $ c = \large\frac{5}{3}$
Hence the slope is $-2$ and $y$ intercept is $ \large\frac{5}{3}$
answered May 7, 2014 by thanvigandhi_1
 

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