Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

If $\;f(x)\;$ is continuous and $\;f(\large\frac{9}{2}) = \large\frac{2}{9}\;$ , then $\;\lim_{x}^{0} f(\large\frac{1-cos 3x}{x^{2}})\;$ is equal to :

$(a)\;\large\frac{9}{2} \qquad(b)\;\large\frac{2}{9} \qquad(c)\;0\qquad(d)\;\large\frac{8}{9} $

Can you answer this question?

1 Answer

0 votes
Given limit can be represented as  ,   f( 9/2 * [sin^2(3x/2)]/[3x/2]^2 ) which as x tends to 0 is  , f(9/2) = 2/9
answered Apr 2, 2015 by Limitsofawesomeness

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App