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JEEMAIN-2014
If the Rolle's theorem holds for the function $\;f(x) = 2x^{3}+ax^{2}+bx\;$ in the interval $\; [-1 ,1]\;$ for the point $\;c=\large\frac{1}{2}\;$ then the value of 2a+b is :
$(a)\;1\qquad(b)\;-1\qquad(c)\;2\qquad(d)\;-2$
jeemain
mathematics
2014
set-01
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asked
May 7, 2014
by
yamini.v
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1 Answer
F(-1)=F(1)
Gives , b=-2
Also, f'(1/2)=0
Gives a=1/2
2a+b=-1
answered
Apr 2, 2015
by
Limitsofawesomeness
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