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JEEMAIN-2014
Let a and b be any two numbers satisfying $\;\large\frac{1}{a^{2}}+\large\frac{1}{b^{2}} =\large\frac{1}{4} \;$, then the foot of perpendicular from the origin on the variable line,$\;\large\frac{x}{a} + \large\frac{y}{b}=1\;$ , lies on
(a) a hyperbola with each semi - axis = $\;\sqrt{2}\;$ \[\](b) a hyperbola with each semi - axis = 2\[\](c) a circle of radius =2\[\](d) a circle of radius =$\;\sqrt{2}$
jeemain
mathematics
2014
set-01
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asked
May 7, 2014
by
yamini.v
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1 Answer
the answe is surely (C)
answered
Apr 5
by
gkseedhar
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