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Mechanical Properties of Solids
Two rods of equal length are in parallel with area in the ratio 3 : 4 and young modulus in the ratio 5 : 3.The ratio of force on the rods is
$\begin{array}{1 1}(A)\;5 : 4\\(B)\;20 : 9\\(C)\;9 : 20\\(D)\;4 : 5\end{array} $
jeemain
physics
class11
ch9
ch10
properties-of-solids-and-liquids
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May 8, 2014
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sreemathi.v
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1 Answer
In parallel the extension is same so
$\Delta l_1=\Delta l_2$
$(\large\frac{F_1}{a_1})\frac{l}{Y_1}=(\large\frac{F_2}{a_2})\frac{l}{Y_2}$
$\large\frac{F_1}{F_2}=\frac{a_1Y_1}{a_2Y_2}$
$\Rightarrow \large\frac{3}{4}\times \frac{5}{3}$
$\Rightarrow \large\frac{5}{4}$
Hence (A) is the correct answer.
answered
May 8, 2014
by
sreemathi.v
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