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# What is change in volume in cc of 5cc of water at surface taken to the bottom of the lake 50m deep,given volume elasticity is $20\times 10^3$atm

$\begin{array}{1 1}(A)\;1.25\times 10^{-3}\\(B)\;2.25\times 10^{-3}\\(C)\;3\times 10^{-3}\\(D)\;\text{None}\end{array}$

Can you answer this question?

$B=20\times 10^3$atm
$\;\;\;=20\times 10^8N/m^2$
$P=Sgh$
$\;\;\;=10^3\times 50$
$\;\;\;=5\times 10^5N/m^2$
As $B=\large\frac{P}{\Delta V/V}$
$\large\frac{\Delta V}{V}=\frac{P}{B}$
$\Rightarrow \large\frac{5\times 10^5}{20\times 10^8}$
$\Rightarrow 2.5\times 10^{-4}$
$\Delta V=2.5\times 10^{-4}\times 5$cc
$\Rightarrow 1.25\times 10^{-3}$
Hence (A) is the correct answer.
answered May 8, 2014