$\begin{array}{1 1}(A)\;1.25\times 10^{-3}\\(B)\;2.25\times 10^{-3}\\(C)\;3\times 10^{-3}\\(D)\;\text{None}\end{array} $

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$B=20\times 10^3$atm

$\;\;\;=20\times 10^8N/m^2$

$P=Sgh$

$\;\;\;=10^3\times 50$

$\;\;\;=5\times 10^5N/m^2$

As $B=\large\frac{P}{\Delta V/V}$

$\large\frac{\Delta V}{V}=\frac{P}{B}$

$\Rightarrow \large\frac{5\times 10^5}{20\times 10^8}$

$\Rightarrow 2.5\times 10^{-4}$

$\Delta V=2.5\times 10^{-4}\times 5$cc

$\Rightarrow 1.25\times 10^{-3}$

Hence (A) is the correct answer.

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