Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

What is change in volume in cc of 5cc of water at surface taken to the bottom of the lake 50m deep,given volume elasticity is $20\times 10^3$atm

$\begin{array}{1 1}(A)\;1.25\times 10^{-3}\\(B)\;2.25\times 10^{-3}\\(C)\;3\times 10^{-3}\\(D)\;\text{None}\end{array} $

Can you answer this question?

1 Answer

0 votes
$B=20\times 10^3$atm
$\;\;\;=20\times 10^8N/m^2$
$\;\;\;=10^3\times 50$
$\;\;\;=5\times 10^5N/m^2$
As $B=\large\frac{P}{\Delta V/V}$
$\large\frac{\Delta V}{V}=\frac{P}{B}$
$\Rightarrow \large\frac{5\times 10^5}{20\times 10^8}$
$\Rightarrow 2.5\times 10^{-4}$
$\Delta V=2.5\times 10^{-4}\times 5$cc
$\Rightarrow 1.25\times 10^{-3}$
Hence (A) is the correct answer.
answered May 8, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App