Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
0 votes

When the load is hang from a string then the ratio of work done by gravity to the work done spring force is

$\begin{array}{1 1}(A)\;1 : 1\\(B)\;2 : 1\\(C)\;1 : 2\\(D)\;1 : 4\end{array} $

Can you answer this question?

1 Answer

0 votes
Work of gravitional force is $=mgx_0$
Where $x_0$ is extension.
Let f be the spring force
$Y=(\large\frac{f}{a})\times \frac{l}{x}$
$Work_{spring}=\int\limits_0^{x_0} fdx$
As $mg=\large\frac{Yax_0}{l}$
$Work_{spring}=\large\frac{mg x_0}{2}$
So $\large\frac{Work_{gravity}}{Work_{spring}}=\frac{mgx_0}{mgx_0/2}$
$\Rightarrow \large\frac{2}{1}$
Hence (B) is the correct answer.
answered May 8, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App