Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Straight Lines
0 votes

Find the distance between parallel lines \[\] $15x+8y-34=0$ and $ 15x+8y+31=0$

$\begin{array}{1 1}(A)\;\large\frac{-65}{17}\: units \\(B)\; \large\frac{65}{17}\: units \\(C)\; \large\frac{|65|}{17}\: units \\(D)\;\text{None of the above} \end{array} $

Can you answer this question?

1 Answer

0 votes
  • Distance between parallel lines is $d=\large\frac{|c_1-c_2|}{\sqrt{A^2+B^2}}$
The given parallel lines are $15x+8y-34=0$ and $15x+8y+31=0$
Here $A = 15, B =8 , C_1=-34\: and \: C_2=31$
Substituting the values we get,
$d = \large\frac{|-34-31|}{\sqrt{15^2+8^2}}$$= \large\frac{|-65|}{17}$
$ = \large\frac{65}{17}$ units.
answered May 9, 2014 by thanvigandhi_1

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, AIPMT Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App