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The base of an equilateral triangle is along the line given by $\;3x+4y=9\;$. If a vertex of the triangle is (1,2) , then the length of a side of the triangle is :

$(a)\;\large\frac{2 \sqrt{3}}{15}\qquad(b)\;\large\frac{4 \sqrt{3}}{15}\qquad(c)\;\large\frac{4 \sqrt{3}}{5}\qquad(d)\;\large\frac{2 \sqrt{3}}{5}$

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