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If $\;2 cos \theta + sin \theta =1 \;(\theta \neq \large\frac{\pi}{2})\;$ , then $\;7 cos \theta + 6 sin \theta\;$ is equal to :

$(a)\;\large\frac{1}{2} \qquad(b)\;\normalsize 2\qquad(c)\;\large\frac{11}{2}\qquad(d)\;\large\frac{46}{5}$

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