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Given $\; Fe^{3+} (aq) + e^{-} \to Fe^{2+} (aq) \; ; E^{0} =+0.77 V \qquad Al^{3+} (aq) + 3e^{-} \to Al (s) \; ; E^{0} =-1.66 V \qquad Br_{2} (aq) +2 e^{-} \to 2 Br^{-} \; ; E^{0} =+1.09V \;$ . Considering the electrode potentials , which of the following represents the correct order of reducing power ?

$(a)\;Fe^{2+} < Al < Br^{-} \qquad(b)\;Br^{-} < Fe^{2+} < Al\qquad(c)\;Al < Br^{-} < Fe^{2+}\qquad(d)\;Al < Fe^{2+} < Br^{-}$

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