Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
0 votes

The distance between gas molecules is doubled on constant temperature,then the pressure is

$\begin{array}{1 1}(A)\;\large\frac{p}{16}\\(B)\;\large\frac{p}{8}\\(C)\;\large\frac{p}{4}\\(D)\;\large\frac{p}{2}\end{array} $

Can you answer this question?

1 Answer

0 votes
T$\rightarrow$ Same
$P\propto v$
Hence (B) is the correct answer.
answered May 12, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App