# 28gm of $N_2$ gas is contained in a flask at a pressure 10atm and at a temperature of $57^{\large\circ}$C.It is found that due to leakage in the flask,the pressure is reduced to half & temperature is reduced to $27^{\large\circ}$C.Quantity of $N_2$ leaked out

$\begin{array}{1 1}(A)\;11/20gm\\(B)\;80/11gm\\(C)\;5/63gm\\(D)\;63/5gm\end{array}$

$PV=nRT$
$V=\large\frac{nRT}{P}$ with constant V
$\large\frac{nT}{P}$=constant
$\large\frac{nT}{P}=\frac{n'T'}{P'}$
$\Rightarrow 63/5$gm
Hence (D) is the correct answer.