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28gm of $N_2$ gas is contained in a flask at a pressure 10atm and at a temperature of $57^{\large\circ}$C.It is found that due to leakage in the flask,the pressure is reduced to half & temperature is reduced to $27^{\large\circ}$C.Quantity of $N_2$ leaked out

$\begin{array}{1 1}(A)\;11/20gm\\(B)\;80/11gm\\(C)\;5/63gm\\(D)\;63/5gm\end{array} $

1 Answer

$V=\large\frac{nRT}{P}$ with constant V
$\Rightarrow 63/5$gm
Hence (D) is the correct answer.
answered May 12, 2014 by sreemathi.v

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