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Home  >>  JEEMAIN and AIPMT  >>  Physics  >>  Class11  >>  Kinetic Theory of Gases
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At temperature T,N molecules of a gas A,each having mass m and at the same temperature,2N molecules of gas B each having mass 2m are filled in a container .$V_{RMS}$ of molecules of B is $V^2$ and $x$ component of $V_{RMS}$ of A is $\omega^2$.$\large\frac{\omega^2}{V^2}$ is

$\begin{array}{1 1}(A)\;1\\(B)\;2\\(C)\;\large\frac{1}{3}\\(D)\;\large\frac{2}{3}\end{array} $

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$\large\frac{\omega^2}{V^2}$ is $\large\frac{2}{3}$
Hence (D) is the correct answer.
answered May 12, 2014 by sreemathi.v

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