An air bubble is released from the bottom of a lake of depth 11m.The temperature at the bottom is $4^{\large\circ}C$ and that at the surface is $12^{\large\circ}C$.What is the ratio of bubble's radius at the surface and its radius at bottom?Assume density of heater is $100Kg/m^3$.Atmospheric pressure =$75$cm of Hg & density of mercury =$13600Kg/m^3$ - Clay6.com, a Free resource for your JEE, AIPMT and Board Exam preparation

An air bubble is released from the bottom of a lake of depth 11m.The temperature at the bottom is $4^{\large\circ}C$ and that at the surface is $12^{\large\circ}C$.What is the ratio of bubble's radius at the surface and its radius at bottom?Assume density of heater is $100Kg/m^3$.Atmospheric pressure =$75$cm of Hg & density of mercury =$13600Kg/m^3$