# An insulated container containing monoatomic gas of molar mass $m$ is moving with velocity $v_0$.If the container is suddenly stopped,find the change in temperature.

$\begin{array}{1 1}(A)\;\large\frac{mv_0^2}{R}\\(B)\;\large\frac{2mv_0^2}{R}\\(C)\;\large\frac{mv_0^2}{3R}\\(D)\;\large\frac{3mv_0^2}{R}\end{array}$

Loss in K.E=$\Delta E=\large\frac{1}{2}$$(mn)v_0^2 Temperature changes by \Delta T,then \large\frac{3}{2}$$nR\Delta T=\large\frac{1}{2}$$mnv_0^2$
$\Delta T=\large\frac{mv_0^2}{3R}$
Hence (C) is the correct answer.