Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming repetition of digits is not allowed

$\begin{array}{1 1}(A)\;50\\(B)\;55\\(C)\;60\\(D)\;65\end{array} $

Can you answer this question?

1 Answer

0 votes
Under the restriction first digit can be selected 5 ways.After the selection of first digit four digits are left.Second digit can be selected in 4 ways and third digit can be selected in 3 ways.
The total number of ways of selecting three digits is $5\times 4\times 3=60$
Hence (C) is the correct answer.
answered May 13, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App