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How many 3-digit numbers can be formed from the digits 1,2,3,4 and 5 assuming repetition of digits is not allowed

$\begin{array}{1 1}(A)\;50\\(B)\;55\\(C)\;60\\(D)\;65\end{array} $

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Under the restriction first digit can be selected 5 ways.After the selection of first digit four digits are left.Second digit can be selected in 4 ways and third digit can be selected in 3 ways.
The total number of ways of selecting three digits is $5\times 4\times 3=60$
Hence (C) is the correct answer.
answered May 13, 2014 by sreemathi.v

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