Ask Questions, Get Answers

Want to ask us a question? Click here
Browse Questions
Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
0 votes

How many 3-digit even numbers can be formed from the digits 1,2,3,4,5,6 if the digits can be repeated?

$\begin{array}{1 1}(A)\;100\\(B)\;104\\(C)\;108\\(D)\;110\end{array} $

Can you answer this question?

1 Answer

0 votes
Let 2 be fixed at unit's place.The ten's place can be filled up in 6 ways.The hundred is place can be also be filled in 6 ways.
No of numbers that can be formed when 2 is at unit's place=$6\times 6=36$
Similarly when 4 is at unit's place,the number of numbers that can be formed =36
Again when 6 is at the unit's place.The number of numbers that can be formed =36
$\therefore$ The total numbers of ways when 3 digits numbers can be formed,the digits being repeated =$36\times 3=108$
Hence (C) is the correct answer.
answered May 13, 2014 by sreemathi.v

Related questions

Ask Question
student study plans
JEE MAIN, CBSE, NEET Mobile and Tablet App
The ultimate mobile app to help you crack your examinations
Get the Android App