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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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Evaluate : $4!-3!$

$\begin{array}{1 1}(A)\;15\\(B)\;17\\(C)\;18\\(D)\;19\end{array} $

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1 Answer

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  • $n!=n(n-1)(n-2).....(3)(2)(1)$
$4!=4\times 3\times 2\times 1$
$\;\;\;\;=24$
$3!=3\times 2\times 1$
$\;\;\;\;=6$
$4!-3!=24-6$
$\;\;\;\;\;\;\;\;\;\;\;=18$
Hence (C) is the correct answer.
answered May 13, 2014 by sreemathi.v
 
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