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Home
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CBSE XI
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Math
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Permutations and Combinations
How many 3-digit numbers can be formed by using the digits 1 to 9,if no digit is repeated?
$\begin{array}{1 1}(A)\;27\\(B)\;500\\(C)\;504\\(D)\;604\end{array} $
cbse
math
class11
bookproblem
ch7
permutations-and-combinations
exercise7-3
q1
sec-a
easy
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asked
May 13, 2014
by
sreemathi.v
retagged
May 13, 2014
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1 Answer
http://clay6.com/mpaimg/mathper-3.png
3-digit numbers are to be formed
(i.e) Three places are to be filled with digits 1 to 9
This can be done in $9\times 8\times 7=504$ ways
Hence (C) is the correct answer.
answered
May 13, 2014
by
sreemathi.v
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