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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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From a committee of 8 persons,in how many ways can we choose a chairman and a vice chairman assuming one person cannot hold more than one position

$\begin{array}{1 1}(A)\;56\\(B)\;58\\(C)\;60\\(D)\;62\end{array} $

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Out of 8 persons chairman can be chosen in 8 ways
After selecting a chairman,we have to choose a vice-chairman out of 7 persons
This can be done in 7 ways
Out of 8 persons,a chairman and a vice chairman can be choosen in $8\times 7=56$ ways
Hence (A) is the correct answer.
answered May 13, 2014 by sreemathi.v

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