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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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How many words can be formed using all letters of the word equation,using each letter exactly once?

$\begin{array}{1 1}(A)\;40300\\(B)\;40310\\(C)\;40320\\(D)\;40000\end{array} $

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  • $nP_r=\large\frac{n!}{(n-r)!}$
Number of letters in equation =8
Number of letters to be taken at a time =8
If P is the number of words thus formed,then
$P=P(8,8)=\large\frac{8!}{(8-8)!}$
$\Rightarrow 8!$
$\Rightarrow 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1$
$\Rightarrow 40320$
Hence (C) is the correct answer.
answered May 13, 2014 by sreemathi.v
 

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