$\begin{array}{1 1}(A)\;40300\\(B)\;40310\\(C)\;40320\\(D)\;40000\end{array} $

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- $nP_r=\large\frac{n!}{(n-r)!}$

Number of letters in equation =8

Number of letters to be taken at a time =8

If P is the number of words thus formed,then

$P=P(8,8)=\large\frac{8!}{(8-8)!}$

$\Rightarrow 8!$

$\Rightarrow 8\times 7\times 6\times 5\times 4\times 3\times 2\times 1$

$\Rightarrow 40320$

Hence (C) is the correct answer.

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