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In how many of the distinct permutations of the letters in MISSISSIPPI do the four $'I'$s not come together?

$\begin{array}{1 1}(A)\;32810\\(B)\;33810\\(C)\;34810\\(D)\;35810\end{array} $

1 Answer

  • $nP_r=\large\frac{n!}{(n-r)!}$
In given word their are $4I,4S,2P$ and $1M$
Total number of permutations with no restriction =$\large\frac{11!}{4!4!2!}$
If take 4I as one letter then total letters become =11-4+1
$\Rightarrow 8$
If P is the permutations when 4i's are not together,then
$\;\;\;=\large\frac{11\times 10\times 9\times 8\times 7\times 6\times 5\times 4 \times 3\times 2 \times 1}{4\times 3\times 2\times 1\times 2\times 1\times 4!}-\frac{8\times 7\times 6\times 5(4!)}{2\times 1(4!)}$
Hence (B) is the correct answer.
answered May 13, 2014 by sreemathi.v

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