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Home  >>  CBSE XI  >>  Math  >>  Permutations and Combinations
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If $nC_8=nC_2$ Find $nC_2$

$\begin{array}{1 1}(A)\;40\\(B)\;45\\(C)\;50\\(D)\;55\end{array} $

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1 Answer

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We have $nC_r=nC_{n-r}$
$nC_2=nC_{n-2}$
$nC_8=nC_{n-2}$
$n-2=8$
$n=8+2$
$n=10$
$nC_2=10C_2$
$\Rightarrow \large\frac{10\times 9}{1\times 2}$
$\Rightarrow 45$
$nC_2=45$
Hence (B) is the correct answer.
answered May 14, 2014 by sreemathi.v
 

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